Master Theorem: T(n) = 2T (n/2) + n/log n = ? I thought the answer would be Θ (nlogn), but the solution says the Master Theorem does not apply. - Quora
T(n) = 3 * T (n / 2) + n * log(n), by using master theorem, which case should be applied here? - Quora
![Solving Recurrence Relations T(n)= 2T(n/2)+n = 2*(2T(n/4)+n/2)+n = 4*T(n/4) +2*n = 8*T(n/8) + 3*n = 2 (log n) * T(1) + (log n) * n = n * 1 + n log Solving Recurrence Relations T(n)= 2T(n/2)+n = 2*(2T(n/4)+n/2)+n = 4*T(n/4) +2*n = 8*T(n/8) + 3*n = 2 (log n) * T(1) + (log n) * n = n * 1 + n log](https://slideplayer.com/7897407/25/images/slide_1.jpg)
Solving Recurrence Relations T(n)= 2T(n/2)+n = 2*(2T(n/4)+n/2)+n = 4*T(n/4) +2*n = 8*T(n/8) + 3*n = 2 (log n) * T(1) + (log n) * n = n * 1 + n log
![The Substitution method T(n) = 2T(n/2) + cn Guess:T(n) = O(n log n) Proof by Mathematical Induction: Prove that T(n) d n log n for d>0 T(n) 2(d n/2. - The Substitution method T(n) = 2T(n/2) + cn Guess:T(n) = O(n log n) Proof by Mathematical Induction: Prove that T(n) d n log n for d>0 T(n) 2(d n/2. -](https://slideplayer.com/4773853/15/images/slide_1.jpg)